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The other tutor did the problem correctly but not by
the 6-step Indian process. Here it is done by the
6-step Indian process.
(1) Get the constant term off the left side of
the equation.
We add 64 to both sides:
x² + 12x - 64 = 0
x² + 12x = 64
(2) Multiply each term in the equation by four
times the coefficient of the x² term.
x² + 12x = 64
The coefficient of x² is 1
Four times 1 is 4
We multiply each term by 4
4x² + 48x = 256
(3) Square the coefficient of the original x term
and add it to both sides of the equation.
The coefficient of the original x term was 12
Square 12, get 144.
Add 144 to both sides:
4x² + 48x = 256
4x² + 48x + 144 = 256 + 144
4x² + 48x + 144 = 400
The left side is a perfect square and may be
written as the square root of the the first
term plus the square root of the third term
in parentheses squared:
(2x + 12)² = 400
(4) Take the square root of both sides.
2x + 12 = ±20
(5) Set the left side of the equation equal to the
positive square root of the number on the right
side and solve for x.
2x + 12 = 20
2x = 8
x = 4
(6) Set the left side of the equation equal to the
positive square root of the number on the right
side and solve for x.
2x + 12 = -20
2x = -32
x = -16
Edwin
