SOLUTION: How do you find the x-intercepts and the vertex of the graph of the function? Could you also graph the vertex if possible, thank you! y=x(x+2)

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: How do you find the x-intercepts and the vertex of the graph of the function? Could you also graph the vertex if possible, thank you! y=x(x+2)      Log On


   

Question 449150: How do you find the x-intercepts and the vertex of the graph of the function? Could you also graph the vertex if possible, thank you!
y=x(x+2)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

y=x(x+2)   |Putting into vertex form

y=x^2 + 2x  |Completing the square

y = (x+1)^2 - 1  |Vertex is (-1,-1) and  Line of symmetry is x = -1