Solve the system of equations.
2x + y = 0
x - 3y + z = 0
3x + y - z = 0
Since z is already eliminated from eq. 1, we
only need to eliminate z from eq. 2 and eq. 3
x - 3y + z = 0
3x + y - z = 0
--------------
4x - 2y = 0
This can be divided thru by 2 to make it
simpler:
2x - y = 0
So we put that together with eq 1 above and we
have this system of 2 equations and 2 unknowns:
2x - y = 0
2x + y = 0
------------
4x = 0
x = 0
substitute x = 0 in
2x - y = 0
2(0) - y = 0
-y = 0
y = 0
Substitute x = 0 and y = 0 in
x - 3y + z = 0
0 -3(0) + z = 0
z = 0
Solution: (x,y,z) = (0,0,0)
Edwin
