SOLUTION: I'm not sure if I'm posting this question in the right place, but here goes: Take a number. Add 1. Square the result. Then subtract from it the product of the original nu

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: I'm not sure if I'm posting this question in the right place, but here goes: Take a number. Add 1. Square the result. Then subtract from it the product of the original nu      Log On


   



Question 44756: I'm not sure if I'm posting this question in the right place, but here goes:
Take a number.
Add 1.
Square the result.
Then subtract from it the product of the original number times two more than the original number.
What did you get?
Will it always be 1.
Can you explain?

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
Take a number.
(x)
Add 1.
(x + 1)
Square the result.
(x + 1)^2
Then subtract from it the product of the original number times two more than the original number.
(x + 1)^2 - x(x + 2)
What did you get?
(x + 1)^2 - x(x + 2)
x^2 + 2x + 1 - x^2 - 2x
x^2 - x^2 + 2x - 2x + 1
1
Will it always be 1. Yes, when you simplify, you get one. Here, I shall graph:
f(x) = (x + 1)^2 - x(x + 2)
+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+x%5E2+%2B+2x+%2B+1+-+x%5E2+-+2x+%29+