SOLUTION: Use completing the square to solve each equation. b^2 - 3b = 5 My answer is no where even close to what the book says it should be. I am in desperate need of help with these ty

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Use completing the square to solve each equation. b^2 - 3b = 5 My answer is no where even close to what the book says it should be. I am in desperate need of help with these ty      Log On


   

Question 44711This question is from textbook Intermediate Algebra
: Use completing the square to solve each equation.
b^2 - 3b = 5
My answer is no where even close to what the book says it should be. I am in desperate need of help with these types of problems. My book says the answer should be (3 + sqrt(29))/2 or (3 - sqrt(29))/2
This is what I came up with. What am I doing wrong?
b^2 - 3b = 5
+b%5E2+-+3b+%2B+%281%2F2%2A3%2F1%29%5E2+=+5+%2B+%281%2F2%2A3%2F1%29%5E2+
+b%5E2+-+3b+%2B+%283%2F2%29%5E2+=+5+%2B+%283%2F2%29%5E2+
+%28b+%2B+3%2F2%29%5E2+=+5+%2B+%283%2F2%29%5E2+
+%28b+%2B+3%2F2%29%5E2+=+5+%2B+%289%2F4%29+
+%28b+%2B+3%2F2%29%5E2+=+%285%2F4%29+%2B+%289%2F4%29+
+%28b+%2B+3%2F2%29%5E2+=+%2814%2F4%29+
+b+%2B+3%2F2+=%2Bplus_minus-%287%2F2%29+
+b+=+-%283%2F2%29%2Bplus_minus-%287%2F2%29+
 This question is from textbook Intermediate Algebra

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
This is what I came up with. What am I doing wrong?
b^2 - 3b = 5
You had b^2-3b+(3/2)^2= 5+(3/2)^2
You factored to get:
(b+(3/2))^2 = 5+(3/2)^2
You should have gotten:
(b-(3/2))^2 = 5+(3/2)^2
Cheers,
Stan H.