SOLUTION: I need help to see the steps to solving this quadratic equation x^ + 12x – 64 = 0 using the method from India

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Question 443383: I need help to see the steps to solving this quadratic equation x^ + 12x – 64 = 0 using the method from India
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-12x%2B-64+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-12%29%5E2-4%2A1%2A-64=400.

Discriminant d=400 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--12%2B-sqrt%28+400+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-12%29%2Bsqrt%28+400+%29%29%2F2%5C1+=+16
x%5B2%5D+=+%28-%28-12%29-sqrt%28+400+%29%29%2F2%5C1+=+-4

Quadratic expression 1x%5E2%2B-12x%2B-64 can be factored:
1x%5E2%2B-12x%2B-64+=+1%28x-16%29%2A%28x--4%29
Again, the answer is: 16, -4. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-12%2Ax%2B-64+%29