SOLUTION: we are doing conics in algebra and we have to put these equation into the standard form for the conic and i am having trouble with these equations. 1) parabola: x^2-2x+8y+9=0 2)

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: we are doing conics in algebra and we have to put these equation into the standard form for the conic and i am having trouble with these equations. 1) parabola: x^2-2x+8y+9=0 2)      Log On


   



Question 441078: we are doing conics in algebra and we have to put these equation into the standard form for the conic and i am having trouble with these equations.
1) parabola: x^2-2x+8y+9=0
2)parabola: x^2-2x+8y+17=0
3)parabola: y^2-4y-4x=0
4)hyperbola; 12x^2-20y^2-12x+40y-37=0
is there any way you can help?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
putting equations into the standard form for the conic
completing the squares
1) parabola: x^2-2x+8y+9=0
(x-1)^2 = -8y - 8
(x-1)^2 = -8(y+1)
2)parabola: x^2-2x+8y+17=0
(x-1)^2 = -8y-16
(x-1)2 = -8(y+2)
3)parabola: y^2-4y-4x=0
(y-2)^2 = 4x + 4
(y-2)^2 = 4(x+1)
4)hyperbola; 12x^2-20y^2-12x+40y-37=0
12[(x-.5)^2 - .25] - 20[(y+1)^2-1] - 37 = 0
12(x-.5)^2 -3 - 20(y+1)^2 + 20 - 37 = 0
12(x-.5)^2 - 20(y+1)^2 = 20
(x-.5)^2/20/12 - (y+1)^2 = 1
%28x-.5%29%5E2%2F%284%2F3%29+-+%28y%2B1%29%5E2%2F1+=+1