SOLUTION: Find the equation of the line of symmetry of the parabola defined by the equation? y=5x^(2)-15x+8

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Question 437529: Find the equation of the line of symmetry of the parabola defined by the equation?
y=5x^(2)-15x+8

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of the line of symmetry of the parabola defined by the equation?
y=5x^(2)-15x+8
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5x^(2)-15x+8
completing the square:
5(x^2-3x+9/4)+8-45/4
5(x-3/2)^2+32/4-45/4
5(x-3/2)^2+13/4
This is a parabola of the form: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the slope or steepness of the curve. Curve opens upwards.
..
In this case, the vertex is at (3/2,13/4).
Equation of line of symmetry: x=3/2
A=5
See graph of parabola below:
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+graph%28+300%2C+300%2C+-5%2C+5%2C+-2%2C10%2C+5%28x-3%2F2%29%5E2%2B13%2F4%29+