SOLUTION: h=-16t^2+64t
A. The object reaches its maximum height 2 seconds after it is propelled. What is the maximum height?
B. After how many seconds does the object hit the ground?
Question 432312: h=-16t^2+64t
A. The object reaches its maximum height 2 seconds after it is propelled. What is the maximum height?
B. After how many seconds does the object hit the ground?
Please help me work this out!!
Thanks,
Chris Found 2 solutions by stanbon, shree840:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! h=-16t^2+64t
A. The object reaches its maximum height 2 seconds after it is propelled. What is the maximum height?
h(2) = -16(2)^2+64(2) = -16*4 + 128 = -64+128 = +64 ft.
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B. After how many seconds does the object hit the ground?
Solve -16t^2+64t = 0
-16t(t-4) = 0
Positive solution:
t = 4 seconds
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Cheers,
Stan H.