SOLUTION: I need help I have solve this quadratic equation, and I want to know if its right is there a way to check? {{{2x^2-4x-3=0}}}...my answer is x=1+

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Question 426848: I need help I have solve this quadratic equation, and I want to know if its right is there a way to check?
...my answer is x=1+ - 2sqrt(5).
thank you.
Found 2 solutions by stanbon, robertb:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
2x^2-4x-3=0
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x = [4 +- sqrt(16-4*2*-3)]/4
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x = [4 +- sqrt(40)]/4
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x = [1 +- (1/2)sqrt(10)]
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Cheers,
Stan H.
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Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website!
Divide both sides of the equation by 2, to get . For complex or radical roots, the conjugate must also be a root. The conjugate of the root that you got is .
The sum of the roots must be equal to -(-2), or 2. This is true, as .
The product of the roots must be -3/2. This is not true, as .
Hence the root that you got is incorrect.

SOLUTION: I need help I have solve this quadratic equation, and I want to know if its right is there a way to check? {{{2x^2-4x-3=0}}}...my answer is x=1+ - 2sqrt(5). thank you.