SOLUTION: Graph the quadratic function. Indicate the vertex coordinates, the axis of symmetry line, the y-intercept, and x-intercepts. y=2x^2-4x+1

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Graph the quadratic function. Indicate the vertex coordinates, the axis of symmetry line, the y-intercept, and x-intercepts. y=2x^2-4x+1      Log On


   



Question 417924: Graph the quadratic function. Indicate the vertex coordinates, the axis of symmetry line, the y-intercept, and x-intercepts.
y=2x^2-4x+1

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
y=2x^2-4x+1 |y-intercept Pt(0,1)
x-intercept when y = 0
2x^2-4x+1 = 0
x+=+%284+%2B-+sqrt%288%29%29%2F%284%29+=+1+%2B-+sqrt%282%29%2F2 = 1 ± .707
Pt(.3,0) and Pt(1.7,0) the x-intercepts (rounded to nearest tenth)
Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex
y=2x^2-4x+1 |completing square to put into the vertex form
y= 2(x-1)^2 -2 +1
y= 2(x-1)^2 -1 Vertex is Pt(1,-1) axis of symmetry is x = 1