SOLUTION: The length of a rectangle is 7 feet less than twice the width. The perimeter is 64 feet. Find the length and width. L= ? feet w= ? feet

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: The length of a rectangle is 7 feet less than twice the width. The perimeter is 64 feet. Find the length and width. L= ? feet w= ? feet      Log On


   

Question 415878: The length of a rectangle is 7 feet less than twice the width. The perimeter is 64 feet. Find the length and width.
L= ? feet
w= ? feet
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x and (2x-7ft) represent the widthe and length respectively

Question states***

  2(2x-7) + 2x = 64ft

Solving for x

   6x = 78

    x = 13ft, the width.  The length is 19ft   (26ft-7ft

CHECKING our Answer***

 2*19ft + 2*13ft = 38ft + 26ft = 64ft