SOLUTION: so i was using the practice questions and the problem was 1xsquared+ -7x +10=0 now after putting it into the formula and doing some work i came to 7 +/- 89 (under the square

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: so i was using the practice questions and the problem was 1xsquared+ -7x +10=0 now after putting it into the formula and doing some work i came to 7 +/- 89 (under the square      Log On


   

Question 415352: so i was using the practice questions and the problem was
1xsquared+ -7x +10=0
now after putting it into the formula and doing some work i came to 7 +/- 89 (under the square root sign). how do i solve from there if 89 doesnt have a perfect square root?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

x^2 - 7x + 10 = 0      |Note the use of ^   (uppercase 6 on Your keyboard

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%287+%2B-+sqrt%28+89+%29%29%2F%282%29+

either leave it in that form or use calculator depending on the instructions.

 x = (7 ± 9.434)/2