SOLUTION: Find b^2-4ac and the number of real solutions to this equation. 5x^2-7=0

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Question 411759: Find b^2-4ac and the number of real solutions to this
equation.
5x^2-7=0
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
b^2-4ac
a=5, b=0, c=-7
-4*5*-7=140
sqrt 140=11.83
two real solutions
(-1.18,0), (1.18,0)