SOLUTION: s=16t^2+v*t+k gives the height of the ball at anytime t in seconds where v is the initial velocity speed in ft/sec and k is the initial height? i am soo confused

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: s=16t^2+v*t+k gives the height of the ball at anytime t in seconds where v is the initial velocity speed in ft/sec and k is the initial height? i am soo confused      Log On


   

Question 411228: s=16t^2+v*t+k gives the height of the ball at anytime t in seconds where v is the initial velocity speed in ft/sec and k is the initial height? i am soo confused
Answer by jjordan95(63) About Me  (Show Source):
You can put this solution on YOUR website!
There is nothing here to answer. The "question" is simply a statement.
-
s=k%2Bvt%2B16t%5E2
-
S is the position of an object at any given time.
k is the initial position. (Where is started.)
v is the initial velocity. (The speed at which it started.)
t is the time.
16t^2 comes from the original equation s=k%2Bvt%2B%281%2F2%29at%5E2, the acceleration due to gravity is 32 feet per second,%281%2F2%29%2832%29t%5E2 gives us 16t^2.
a is the acceleration.
-
This is a simplified version of the equation. The information above is not totally correct, but it is simplified so that you can understand the basic concept.
===========================================================================================================
If you simply need to put this into the quadratic formula, x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+, then, looking at the equation, s=k%2Bvt%2B16t%5E2, you can find
a=16
b=v
c=k
v and k are explained above.