SOLUTION: please help find the possible value or values of y in the quadratic equation {{{4-4y-y^2=0}}}? PLEASE HELP

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: please help find the possible value or values of y in the quadratic equation {{{4-4y-y^2=0}}}? PLEASE HELP      Log On


   

Question 40555: please help
find the possible value or values of y in the quadratic equation 4-4y-y%5E2=0? PLEASE HELP
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
4-4y-y%5E2=0
multiply both sides by -1
y%5E2+%2B+4y+-+4+=+0
y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
y+=+%28-4+%2B-+sqrt%28+4%5E2-4%2A1%2A%28-4%29+%29%29%2F%282%2A1%29+
y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
y+=+%28-4+%2B-+sqrt%28+16+%2B+16+%29%29%2F%282%2A1%29+
y+=+-2+%2B-sqrt%282%29%2A2
y+=+2%28-1+%2B-sqrt%282%29%29
so, the answers are
y+=+2%28-1+%2B+sqrt%282%29%29
and
y+=+2%28-1+-+sqrt%282%29%29