SOLUTION: please help what are the factors of {{{m^2-14m+48}}}?

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Question 40544: please help
what are the factors of m%5E2-14m%2B48?
Found 3 solutions by checkley71, Nate, Earlsdon:
Answer by checkley71(8403) About Me  (Show Source):
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
m%5E2-14m%2B48
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation am%5E2%2Bbm%2Bc=0 (in our case 1m%5E2%2B-14m%2B48+=+0) has the following solutons:

m%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-14%29%5E2-4%2A1%2A48=4.

Discriminant d=4 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--14%2B-sqrt%28+4+%29%29%2F2%5Ca.

m%5B1%5D+=+%28-%28-14%29%2Bsqrt%28+4+%29%29%2F2%5C1+=+8
m%5B2%5D+=+%28-%28-14%29-sqrt%28+4+%29%29%2F2%5C1+=+6

Quadratic expression 1m%5E2%2B-14m%2B48 can be factored:
1m%5E2%2B-14m%2B48+=+1%28m-8%29%2A%28m-6%29
Again, the answer is: 8, 6. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-14%2Ax%2B48+%29

%28m+-+8%29%28m+-+6%29

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Try this:
The factor will be of the form (m+a)(m+b) where:
(a)(b) = +48
a + b = -14
The obvious candidates for a and b are 6 and 8, but since you need their sum to be -14, then -6 and -8 would be more logical choices. Let's try them, using FOIL.
%28m-6%29%28m-8%29+=+m%5E2+-+8m+-+6m+%2B+48 Simplifying, you get m%5E2+-+14m+%2B+48
The factors are: (m-6)(m-8)