Question 404151: Could you please tell me how I would solve this question?:The sum of the squares of two consecutive positive odd integers is 202. find the integers.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The sum of the squares of two consecutive positive odd integers is 202. find the integers.
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1st odd: 2x-1
2nd odd: 2x+1
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Equation:
(2x-1)^2 + (2x+1) = 202
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4x^2-4x+1 + 4x^2+4x+1 = 202
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8x^2+2 = 202
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4x^2+1 = 101
4x^2 = 100
x^2 = 25
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x = 5 or x = -5
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If x = 5,
2x-1 = 9
2x+1 = 11
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If x = -5
2x-1 = -11
2x+1 = -9
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Cheers,
Stan H.
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