SOLUTION: 4x^2=27x+7

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Question 400635: 4x^2=27x+7
Answer by sofiyac(983) About Me  (Show Source):
You can put this solution on YOUR website!
+4x%5E2=27x%2B7+ move everything to the left side, so subtract 27x from each side and subtract 7 from each side.
+4x%5E2-27x-7=27x-27x%2B7-7+
+4x%5E2-27x-7=0+ now we factor
+%284x%2B1%29%28x-7%29=0+ now set each part equal to zero and solve for x
4x+1=0
4x=-1
x=-1/4
x-7=0
x=7