SOLUTION: f(x) = −x^2 + 6x + 1 Graph

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Question 399550: f(x) = −x^2 + 6x + 1
Graph
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x) = -x^2 + 6x + 1    |completing the square

f(x) = -[(x-3)^2 - 9] + 1 

f(x) = -(x-3)^2 +10  vertex is Pt(3,10) Line of symmetry  x= 3