SOLUTION: How would you solve this? m4 +13m2 − 48 = 0 would you separate the equation out so it's m2(m2+13)-48=0?

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Question 396120: How would you solve this?
m4 +13m2 − 48 = 0
would you separate the equation out so it's
m2(m2+13)-48=0?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming the 4 and 2 are exponents,
m%5E4+%2B+13m%5E2+-+48+=+0
Sub x for m^2
x%5E2+%2B+13x+-+48+=+0
(x+16)(x-3) = 0
x = 3, -16
----------
Sub back
m%5E2+=+3
m = ± sqrt(3)
------------
m%5E2+=+-16
m = ± 4i
================
m%5E4+%2B+13m%5E2+-+48+=+0
You might factor that, too.
m%5E2+%2B+16%29%28m%5E2+-+3%29+=+0
Same answers, simpler, but if factoring isn't possible, substitution always works.