Hi 3x2 + 9x + 1 = 0 x is {-0.1156, -2.8844} finding vertex by completing square the vertex form of a parabola, where(h,k) is the vertex y = 3(x^2 + 3) + 1 y = 3[(x+3/2)^2 - 9/4] + 1 y = 3(x + 3/2)^2 -23/4 Vertex is Pt(-3/2,-23/4)