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y = x² + 5x - 14
We substitute 0 for y
0 = x² + 5x - 14
x² + 5x - 14 = 0
We factor:
(x + 7)(x - 2) = 0
We use the zero factor principle:
x + 7 = 0 x - 2 = 0
x = -7 x = 2
So the graph crosses the x axis at the two points
(-7,0) and at (2,0), as we see on the graph below:
Edwin