SOLUTION: x^2-4x+7=0
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Question 393061
:
x^2-4x+7=0
Answer by
edjones(8007)
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x^2-4x+7=0
x^2-4x =-7
x^2-4x+4=-7+4 completing the square.
(x-2)^2=-3
x-2=+-sqrt(-3)
x=2+-sqrt(3)i
x=2-sqrt(3)i, x=2+sqrt(3)i
.
Ed