Hi, Parabola with vertex at pt(-6,-1) and x-intercepts are (-9,0) and (-3,0) Using the vertex form of a parabola, where(h,k) is the vertex y = a(x+6)^2 - 1 Using Pt(-3,0) to solve for a 0 = a *3^2 - 1 1 = 9a 1/9 = a y = 1/9(x+6)^2 - 1