Question 391016: what is the equation of the quadratic function with roots 0 and 1 and a vertex at (1/2,-2/33)?
Found 3 solutions by stanbon, ewatrrr, solver91311:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! what is the equation of the quadratic function with roots 0 and 1 and a vertex at (1/2,-2/33)?
----
Using the two roots.
Form: y = a(x-0)(x-1)
y = ax(x-1)
----
Using (1/2,-2/33)
-2/33 = a(1/2)(-1/2)
---
-2/33 = -a/4
a = 8/33
----
Equation:
y = (8/33)x(x-1)
=====================
Cheers,
Stan H.
======================
Answer by ewatrrr(24785)  (Show Source):
You can put this solution on YOUR website!
Hi
parabola with vertex at (1/2,-2/33) and x-inercepts of (0,0) and (1,0)
Using the vertex form of a parabola,  where(h,k) is the vertex
y = a(x - 1/2)^2 - 2/33 using Pt(0,0) to solve for a
0 = a(-1/2)^2 - 2/33
2/33 = (1/4)a
8/33 = a
y = 8/33(x-1/2)^2 - 2/33
Answer by solver91311(24713)  (Show Source):
|
|
|
