SOLUTION: A rectangle field is going to be completely enclosed by 100m of fencing. Determine the dimensions of the field that will result in an area of 575m square. Round your answer to the

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A rectangle field is going to be completely enclosed by 100m of fencing. Determine the dimensions of the field that will result in an area of 575m square. Round your answer to the       Log On


   



Question 390023: A rectangle field is going to be completely enclosed by 100m of fencing. Determine the dimensions of the field that will result in an area of 575m square. Round your answer to the nearest tenth of a metre.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangle area:
A+=+ab....where a and b are length and width
given:
A+=575m%5E2 and 100m for fencing which is equal to perimeter P+=+2%28a%2Bb%29
to find: a and b
use
ab+=575m%5E2 and 100m+=+2%28a%2Bb%29 and solve the system

ab+=575m%5E2...solve for a
a+=575m%5E2%2Fb........substitute in 100m+=+2%28a%2Bb%29 and find b

cross%28100%2950m+=+cross%282%29%28%28575m%5E2%2Fb%29%2Bb%29

50m+=+%28575m%5E2%2Fb%29%2Bb...both sides multiply by b

50m+%2Ab=+b%28575m%5E2%2Fb%29%2Bb%2Ab

50m+%2Ab=+cross%28b%29%28575m%5E2%2Fcross%28b%29%29+%2Bb%5E2

50m+%2Ab=+575m%5E2+%2Bb%5E2

50m+%2Ab-+b%5E2=+575m%5E2


-+b%5E2+%2B+50m+%2Ab+-575m%5E2+=0...solve for b

Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic


ax%5E2%2Bbx%2Bc=0


the general solution using the quadratic equation is:


x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29




So lets solve -x%5E2%2B50%2Ax-575=0 ( notice a=-1, b=50, and c=-575)





x+=+%28-50+%2B-+sqrt%28+%2850%29%5E2-4%2A-1%2A-575+%29%29%2F%282%2A-1%29 Plug in a=-1, b=50, and c=-575




x+=+%28-50+%2B-+sqrt%28+2500-4%2A-1%2A-575+%29%29%2F%282%2A-1%29 Square 50 to get 2500




x+=+%28-50+%2B-+sqrt%28+2500%2B-2300+%29%29%2F%282%2A-1%29 Multiply -4%2A-575%2A-1 to get -2300




x+=+%28-50+%2B-+sqrt%28+200+%29%29%2F%282%2A-1%29 Combine like terms in the radicand (everything under the square root)




x+=+%28-50+%2B-+10%2Asqrt%282%29%29%2F%282%2A-1%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




x+=+%28-50+%2B-+10%2Asqrt%282%29%29%2F-2 Multiply 2 and -1 to get -2


So now the expression breaks down into two parts


x+=+%28-50+%2B+10%2Asqrt%282%29%29%2F-2 or x+=+%28-50+-+10%2Asqrt%282%29%29%2F-2



Now break up the fraction



x=-50%2F-2%2B10%2Asqrt%282%29%2F-2 or x=-50%2F-2-10%2Asqrt%282%29%2F-2



Simplify



x=25-5%2Asqrt%282%29 or x=25%2B5%2Asqrt%282%29



So the solutions are:

x=25-5%2Asqrt%282%29 or x=25%2B5%2Asqrt%282%29




one solution
b=25-5sqrt%282%29=25-5%2A1.41=+25-7.05=+17.95m

b=+17.95m
other solution
b=25%2B5sqrt%282%29=25%2B5%2A1.41=+25%2B7.05=+32.05m
b=+32.05m
now find a
one solution
a+=575m%5E2%2F17.95m

a+=32.03m
other solution
a+=575m%5E2%2F32.05m
a+=17.94m

so, dimensions are:

a+=32.03m

b=+17.95m

or

a+=17.94m
b=+32.05m

check:
100m+=+2%28a%2Bb%29
100m+=+2%2832.03m%2B17.94m%29
100m+=+2%2849.97m%29..round decimal number to nearest whole number

100m+=+2%2850m%29

100m+=+100m