SOLUTION: A toy rocket is launched from the top of a mountain and falls on the ground below. The height of the rocket above the ground is modeled by the relation H= -5t 2 + 20t + 105 where H

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Question 389810: A toy rocket is launched from the top of a mountain and falls on the ground below. The height of the rocket above the ground is modeled by the relation H= -5t 2 + 20t + 105 where H is the height in meters and t is the elapsed time in seconds. How high is the mountain?
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
Answer by stanbon(75887) About Me  (Show Source):
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A toy rocket is launched from the top of a mountain and falls on the ground below. The height of the rocket above the ground is modeled by the relation
H(t) = -5t^2 + 20t + 105 where H is the height in meters and t is the elapsed time in seconds. How high is the mountain?
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The height of the mountain is the height of the rocket
at time t=0.
H(0) = -5*0^2+20*0+105 = 105 meters.
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Cheers,
Stan H.
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