SOLUTION: {{{sqrt(18)-3sqrt(8)+sqrt(50)}}} {{{sqrt(2 x9)-3sqrt(2x4)+sqrt(2x25)}}} {{{2sqrt(3)-6sqrt(2) +2sqrt(5)}}} {{{(2-6+2)sqrt(3-2+5)}}} {{{-2sqrt(6)}}} {{{-2sqrt(3)}}} are my step
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-> SOLUTION: {{{sqrt(18)-3sqrt(8)+sqrt(50)}}} {{{sqrt(2 x9)-3sqrt(2x4)+sqrt(2x25)}}} {{{2sqrt(3)-6sqrt(2) +2sqrt(5)}}} {{{(2-6+2)sqrt(3-2+5)}}} {{{-2sqrt(6)}}} {{{-2sqrt(3)}}} are my step
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Question 38514
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are my steps right? if not, can you please correct it for me
Answer by
Nate(3500)
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You can
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the square root of 9 is 3 and the square root of 25 is 5 .... but the square root of 2 doesn't come out to an integer