SOLUTION: Derive the Maclaurin series for sin x as sin x = x-x^3/3!+x^5/5! - ... Thank You

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Question 383605: Derive the Maclaurin series for sin x as
sin x = x-x^3/3!+x^5/5! - ...
Thank You
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Find the derivatives of y=sin%28x%29 where the number after f is the number of times f has been differentiated.
f1%28x%29=cos%28x%29
f2%28x%29=-sin%28x%29
f3%28x%29=-cos%28x%29
f4%28x%29=sin%28x%29
f5%28x%29=cos%28x%29
Expanded about x=0,

f%280%29=sin%280%29=0
f1%280%29=cos%280%29=1
f2%280%29=-sin%280%29=0
f3%280%29=-cos%280%29=-1
f4%280%29=sin%280%29=0
f5%280%29=cos%280%29=1
.
.

sin%28x%29=x-%28x%5E3%2F3%21%29%2B%28x%5E5%2F5%21%29