SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of F(x). Graph the function. f(x) +1/3(x+6)^2+5

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of F(x). Graph the function. f(x) +1/3(x+6)^2+5      Log On


   

Question 380723: Find the vertex, the line of symmetry, and the maximum or minimum value of F(x). Graph the function.
f(x) +1/3(x+6)^2+5
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

If I am understanding your question properly:

f(x)= 1/3(x+6)^2 + 5

the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

vertex is Pt(-6,5), line of symetry is x = -6

a = 1/3, is a positive nunber, therefore the parabola opens upward:

Minimum value of f(x) is 5

graph( 300, 300, -6, 6, -6, 6))}}}