SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). f(x)= -(x+2)^2-4

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). f(x)= -(x+2)^2-4       Log On


   



Question 379481: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x).
f(x)= -(x+2)^2-4

Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Vertex is the point (-2, -4).
Line of symmetry is x = -2.
Since a < 0 (equal to -1), parabola opens downward, so it will have a maximum. Maximum value is -4.