SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). f(x)= -(x+2)^2-4
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-> SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). f(x)= -(x+2)^2-4
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Question 379481
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Find the vertex, the line of symmetry, and the maximum or minimum value of f(x).
f(x)= -(x+2)^2-4
Answer by
robertb(5830)
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Vertex is the point (-2, -4).
Line of symmetry is x = -2.
Since a < 0 (equal to -1), parabola opens downward, so it will have a maximum. Maximum value is -4.