SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). F(x)=-(x+2)^2-4

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). F(x)=-(x+2)^2-4      Log On


   

Question 379471: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x).
F(x)=-(x+2)^2-4
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The equation is already in vertex form, y=a%28x-h%29%5E2%2Bk.
Vertex : (-2,-4)
The vertex lies on the axis of symmetry x=-2.
Since a=-1%3C0, the value at the vertex is a maximum.
y%5Bmax%5D=-4
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