SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function on paper. f(x)=x^2-8x-1

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function on paper. f(x)=x^2-8x-1      Log On


   

Question 379460: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function on paper.
f(x)=x^2-8x-1
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
The vertex of the quadratic is -b/2a = 4. Therefore the line of symmetry is x=4. Since the polynomial has a positive x^2 coefficient, the graph points upward, therefore x=4 must result in an absolute minimum. This value is just f(4) = -17.