SOLUTION: For all values of n and r, where r ≤ n, does nCr always equal nCn-r? Why or why not? NO? I am so confused

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Question 373895: For all values of n and r, where r ≤ n, does nCr always equal nCn-r? Why or why not?
NO? I am so confused
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
nCr = nCn-r, considering the definition: nCr+=+n%21%2F%28r%21%28n-r%29%21%29.
Now .
Therefore nCr = nCn-r.