SOLUTION: A model rocket is launched straight up from a platform. The height of the rocket is given by h(t)=-16t^2+266t+10 a. What is the altitude of the rocket 2 seconds after launching?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: A model rocket is launched straight up from a platform. The height of the rocket is given by h(t)=-16t^2+266t+10 a. What is the altitude of the rocket 2 seconds after launching?      Log On


   

Question 371786: A model rocket is launched straight up from a platform. The height of the rocket is given by h(t)=-16t^2+266t+10
a. What is the altitude of the rocket 2 seconds after launching?
b. How high does the rocket go?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
a. plug in 2 for t and find h(2)

b. the max value for h is the vertex of the parabola, which lies on the axis of symmetry
___ the general equation for the axis of symmetry is ___ x = -b / (2a)
___ in this case ___ t = -266 / [2(-16)] ___ plug in this value of t to find the max height