SOLUTION: Identify the values of a, b, and c you would substitute into the quadratic formula to solve each of the following; a) -2x^2 - 23x + 6 = 3x^2 + 15x b) (x + 2) (x - 3) = (2x - 1)

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Identify the values of a, b, and c you would substitute into the quadratic formula to solve each of the following; a) -2x^2 - 23x + 6 = 3x^2 + 15x b) (x + 2) (x - 3) = (2x - 1)      Log On


   

Question 371437: Identify the values of a, b, and c you would substitute into the quadratic formula to solve each of the following;
a) -2x^2 - 23x + 6 = 3x^2 + 15x
b) (x + 2) (x - 3) = (2x - 1) (x - 4)
Answer by lefty4ever26(59) About Me  (Show Source):
You can put this solution on YOUR website!
Quadratic Formula x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a) -2x%5E2-23x%2B6=3x%5E2%2B15x Need to get everything in the equation to one side and have it equal to 0.
-5x%5E2-38x%2B6=0 A quadratic equation is ax%5E2%2Bbx%2Bc=0
So a=-5
b=-38
c=6
Plug these values into the quadratic formula (above) and solve for x. Remember there will be two values for x because of the + or -.
b) %28x%2B2%29%28x-3%29=%282x-1%29%28x-4%29 Foil both sides then get everything to one side and set equal to 0.
x%5E2-x-6=2x%5E2-9x%2B4
-x%5E2%2B8x-10=0
So a=-1
b=8
c=-10
Plug these into the Quadratic Formula and solve for x.