SOLUTION: how do i find the completion of squares for the equation y2-5y+6=0

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Question 371345: how do i find the completion of squares for the equation y2-5y+6=0
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

y^2-5y+6=0

Factoring

(y-3)(y-2) = 0 Note inner product(-3y) and outer product (-2y) have a sum of -5y

(y-3)=0

y = 3

(y-2) = 0 

y = 2

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how do i find the completion of squares for the equation
y^2-5y+6=0
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y^2-5y+? = -6+?
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Complete the square:
y^2-5y+(5/2)^2 = -6+(5/2)^2
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Factor the left side:
(y-(5/2))^2 = (-24/4)+(25/4)
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(y-(5/2))^2 = = 1/4
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y-(5/2) = 1/2 or y-(5/2) = -1/2
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y = 3 or y = 2
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Cheers,
Stan H.