SOLUTION: 5x^4-12x^3=0 these exponents are blowing my mind.

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Question 36976: 5x^4-12x^3=0
these exponents are blowing my mind.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Think of exponents in the simplest way possible. Forget x, y, z, etc.
2 is a simple number (1 is really too simple for this)
2%2A2%2A2%2A2+=+2%5E4
count up the # of 2's - that's the exponent
2%2A2%2A2%2A2%2A2%2A2%2A2+=+2%5E7
now multiply
2%2A2%2A2%2A2%2A2%2A2%2A2%2A2%2A2%2A2%2A2+=+2%5E11
you just add the exponents
It's a lot easier to write 2%5E4+%2A+2%5E7+=+2%5E11 than all those 2's
That's the point of exponents- it's EASIER
but you have to acquire rules
like how do you add? 2%5E7+%2B+2%5E4
not obvious
2%5E7+%2B+2%5E4+=+2%5E4%2A%282%5E3+%2B+1%29
do it the long way, too
2%2A2%2A2%2A2%2A2%2A2%2A2+%2B+2%2A2%2A2%2A2+=+2%2A2%2A2%2A2+%2A+%282%2A2%2A2+%2B+1%29
I just factored out 2*2*2*2
go back and forth
easy way - hard way
easy way - hard way
If you play with it enough and show yourself what's true and
what isn't- you'll have no trouble with the x's, y's, and z's
5%2Ax%5E4+-+12%2Ax%5E3+=+0
x%5E3+%2A+%285%2Ax+-+12%29+=+0
I factored out x^3
what makes this true?
If x is zero, I get
0 times something = 0
that's certainly true
Inside the parenthesis, if x= 12/5, then
12/5*(12/5 - 12/5) = 0
that's certainly true, also
x = 0
x = 12/5
are the solutions