SOLUTION: the roots 2x^2-3x+c=0 are imaginary if c equals

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Question 369077: the roots 2x^2-3x+c=0 are imaginary if c equals
Found 2 solutions by jsmallt9, CharlesG2:
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
b%5E2-4ac is called the discriminant. Its value will tell you how many roots of what type there are for a quadratic equation:
  • b%5E2-4ac+%3E+0 means that there are two real roots.
  • b%5E2-4ac+=+0 means that there are one real root.
  • b%5E2-4ac+%3C+0 means that there are two complex roots. And if b = 0 then the complex roots are imaginary roots (i.e. the real part of the complex number will be zero).

The a, b and c for the discriminant come from the general form for quadratic equations: ax%5E2+%2B+bx+%2B+c+=+0. Looking at your equation, a = 2, b = -3 and c = c. This makes the discriminant:
%28-3%29%5E2+-4%282%29%28c%29
which simplifies as follows:
9+-+4%282%29c
9+-+8c
If we want complex roots then we want
9+-+8c+%3C+0
Solving this I'll start by subtracting 9 from each side:
-8c+%3C+-9
Then dividing by -8. (Remember that whenever an inequaity is multiplied or divided by any negative number, like we are doing now, the inequality symbol must be reversed! This is why we have a "greater than" all of a sudden.)
c+%3E+9%2F8

NOTE: Since your b is not zero, there is no way to get imaginary roots.

Answer by CharlesG2(834) About Me  (Show Source):
You can put this solution on YOUR website!
the roots 2x^2-3x+c=0 are imaginary if c equals

use the discriminant part of the quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
where a = 2, b = -3, c = c
the discriminant is b^2 - 4ac
b^2 - 4ac = (-3)^2 - 4(2)c
b^2 - 4ac = 9 - 8c
if 9 - 8c is less than 0 than the roots are imaginary
9 - 8c < 0
-8c < -9
8c > 9, flipped sign since divided by -1
c > 9/8
if c is greater than 9/8

b does not equal 0, so the results will be complex numbers
a complex number has a real part and an imaginary part
so the answers will not be imaginary numbers
(meaning for example in the case a + bi, a = 0,
the bi is an imaginary number)
instead they will be complex numbers