SOLUTION: find vertex and axis of symmetry {{{ h(x)=2x^2-16x+25 }}}

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Question 368573: find vertex and axis of symmetry
+h%28x%29=2x%5E2-16x%2B25+
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square to convert to vertex form, y=a%28x-h%29%5E2%2Bk
h%28x%29=2x%5E2-16x%2B25
h%28x%29=2%28x%5E2-8x%29%2B25
h%28x%29=2%28x%5E2-8x%2B16%29%2B25-2%2816%29
h%28x%29=2%28x-4%29%5E2%2B25-32
h%28x%29=2%28x-4%29%5E2-7
The vertex is (4,-7) and the vertex lies on the axis of symmetry x=4.
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