SOLUTION: find vertex, axis of symmetry and the minimum or maximum value {{{ f(x)=(x+3)^2-2 }}}

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: find vertex, axis of symmetry and the minimum or maximum value {{{ f(x)=(x+3)^2-2 }}}      Log On


   

Question 368554: find vertex, axis of symmetry and the minimum or maximum value
+f%28x%29=%28x%2B3%29%5E2-2+
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The parabola is already in vertex form.
Vertex: (-3,-2)
The vertex lies on the axis of symmetry, x=-3.
Since a=1%3E0 the parabola opens upwards, the vertex value is the function minimum.
y%5Bmin%5D=-2
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