SOLUTION: Solving (2x+3)(2x+5)(x-1)(x-2)=30, the roots available are :

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Question 367560: Solving (2x+3)(2x+5)(x-1)(x-2)=30, the roots available are :
Found 2 solutions by lefty4ever26, Fombitz:
Answer by lefty4ever26(59) About Me  (Show Source):
You can put this solution on YOUR website!
Set each of the factors () =to 30 Then solve for x...Those will be the roots where the graph crosses the x-axis.
2x+3=30 , 2x+5=30 , x-1=30 , x-2=30
x=27/2 x=25/2 x=31 x=32
So your roots are at x=(27/2),(25/2),31,32


Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Multiply out the left hand side.
%282x%2B3%29%282x%2B5%29%28x-1%29%28x-2%29=%284x%5E2%2B10x%2B6x%2B15%29%28x%5E2-2x-x%2B2%29
%282x%2B3%29%282x%2B5%29%28x-1%29%28x-2%29=%284x%5E2%2B16x%2B15%29%28x%5E2-3x%2B2%29
%282x%2B3%29%282x%2B5%29%28x-1%29%28x-2%29=4x%5E4%2B4x%5E3-25x%5E2-13x%2B30
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4x%5E4%2B4x%5E3-25x%5E2-13x%2B30=30
4x%5E4%2B4x%5E3-25x%5E2-13x=0
x%284x%5E3%2B4x%5E2-25x-13%29=0
x%282x%2B1%29%282x%5E2%2Bx-13%29=0
Four real solutions:
highlight%28x=0%29
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2x%2B1=0
2x=-1
highlight%28x=-1%2F2%29
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2x%5E2%2Bx-13=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A2%2A%28-13%29+%29%29%2F%282%2A2%29+
highlight%28x+=+%28-1+%2B-+sqrt%28+105+%29%29%2F%284%29%29+