SOLUTION: What is the vertex of f(x)=x^2-4, and how did you figure it out? Thank you so much for your help!

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: What is the vertex of f(x)=x^2-4, and how did you figure it out? Thank you so much for your help!      Log On


   

Question 365523: What is the vertex of f(x)=x^2-4, and how did you figure it out?
Thank you so much for your help!
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the general vertex form of the equation is ___ f(x) = a(x - h)^2 + k

"a" is the coefficient of the second order (squared) term , and (h,k) is the vertex

fitting your equation to the general form ___ f(x) = 1(x - 0)^2 + (-4)