SOLUTION: One number is three less than twice another. The sum of their squares is 74. Find the numbers.

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Question 364851: One number is three less than twice another. The sum of their squares is 74. Find the numbers.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
One number is three less than twice another. The sum of their squares is 74. Find the numbers.
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1st: x
2nd: 2x-3
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Equation:
x^2 + (2x-3)^2 = 74
x^2 + 4x^2 -12x + 9 = 74
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5x^2 -12x - 65 = 0
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(x-5)(5x+13) = 0
1st: x = 5
2nd: 2x-3 = 7
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Cheers,
stan H.