SOLUTION: This one is so hard for me :( Could you help me out? I posted this before but got no response. Thanks!!! Apply the quadratic formula to find the roots of the given function, and

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: This one is so hard for me :( Could you help me out? I posted this before but got no response. Thanks!!! Apply the quadratic formula to find the roots of the given function, and      Log On


   

Question 36439: This one is so hard for me :( Could you help me out? I posted this before but got no response. Thanks!!!
Apply the quadratic formula to find the roots of the given function, and then graph the function.
g(x) = x^2 + x + 12
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a=1, b=1, c=12
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B1x%2B12+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%281%29%5E2-4%2A1%2A12=-47.

The discriminant -47 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -47 is + or - sqrt%28+47%29+=+6.85565460040104.

The solution is

Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B12+%29

Hope this helps.
Cheers,
Stan H.