SOLUTION: Hi There, I was hoping someone could guide me through this problem. If it's not too much trouble, I am looking for the steps to solve to be included in the answer. Directions:

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Hi There, I was hoping someone could guide me through this problem. If it's not too much trouble, I am looking for the steps to solve to be included in the answer. Directions:       Log On


   



Question 360222: Hi There, I was hoping someone could guide me through this problem. If it's not too much trouble, I am looking for the steps to solve to be included in the answer.
Directions: Solve
A ladder that is 10ft long is 6ft from the base of the wall. How far up the wall does the ladder reach?

Found 2 solutions by checkley77, JBarnum:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
You have a right triangle with a base=6ft.
The hypotenuse=10 ft.
Using the formula:
a^2+b^2=c^2
6^2+b^2=10^2
36+b^2=100
b^2=100-36
b^2=64
b=sqrt64
b=8 ft is the height up the wall that the ladder reaches.

Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
this is actually a geometry problem using the Pythagorean Theorem a%5E2%2Bb%5E2=c%5E2
the ladder leaning against the wall makes a triangle with the ground. the base of ground is 6ft the hypotenuse in this case is the length of the ladder at 10 ft so the missing side is the length of the wall
a and b represent the 2 smaller sides and c represents the hypotenuse
a=6 b=? and c=10
plug them in the equatioN
a%5E2%2Bb%5E2=c%5E2
6%5E2%2Bb%5E2=10%5E2
36%2Bb%5E2=100
b%5E2=64
highlight%28b=8%29