SOLUTION: Algebra: Find the vertex, symmetry, maximum, and minimum of f(x)=-x^2+12x+1.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Algebra: Find the vertex, symmetry, maximum, and minimum of f(x)=-x^2+12x+1.      Log On


   

Question 353026: Algebra: Find the vertex, symmetry, maximum, and minimum of f(x)=-x^2+12x+1.
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Here, a=1, b=12, c=1.
The x-coordinate of the vertex is -b%2F2a. The y-coordinate of the vertex is %284%2Aa%2Ac-b%5E2%29%2F%284a%29.
-b%2F2a=-12%2F%282%2A1%29=-6.
%284%2Aa%2Ac-b%5E2%29%2F%284a%29=%284%2A1%2A1-144%29%2F%284%2A1%29=-35.
The axis of symmetry is the vertical line x=-6.
There is no max value. (The parabola opens upward.)
The minimum value is y+=+-35.