SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). F(x)=1/5(x+1)^2+7 Any help is greatly appreciated. These always confuse me. Thank you in ad

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). F(x)=1/5(x+1)^2+7 Any help is greatly appreciated. These always confuse me. Thank you in ad      Log On


   

Question 352586: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x).
F(x)=1/5(x+1)^2+7
Any help is greatly appreciated. These always confuse me.
Thank you in advance!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Confused how?
The equation is already in vertex form, y=a%28x-h%29%5E2%2Bk, where (h,k) is the vertex.
Compare to the given equation to find the vertex, (h,k).
The line of symmetry lies on the vertex, so x=h
Whether the parabola opens upwards or downwards is determined by the sign of a.
If a%3E0, then the vertex value is a minimum, y%5Bmin%5D=k
If a%3C0, then the vertex value is a maximum, y%5Bmax%5D=k