SOLUTION: I'm having some trouble with a quadratic equation problem. The problem is (3x+1)^2=9

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Question 345288: I'm having some trouble with a quadratic equation problem. The problem is
(3x+1)^2=9
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%283x%2B1%29%5E2=9 Start with the given equation.


3x%2B1=%22%22%2B-sqrt%289%29 Take the square root of both sides.


3x%2B1=sqrt%289%29 or 3x%2B1=-sqrt%289%29 Break up the "plus/minus" to form two equations.


3x%2B1=3 or 3x%2B1=-3 Take the square root of 9 to get 3.


3x=-1%2B3 or 3x=-1-3 Subtract 1 from both sides.


3x=2 or 3x=-4 Combine like terms.


x=2%2F3 or x=-4%2F3 Divide both sides by 3 to isolate x.


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Answer:


So the solutions are x=2%2F3 or x=-4%2F3.